Practice Problem ANSWERS: Correlation

November 3, 2008 by  
Filed under Calc Solutions

Item 1

What is the correlation between these two variables:

Stress         Sense of Humor 
    4                     2 
  10                     8 
  12                   11 
    5                     3 
    7                     8 
    6                     7 
    2                     3 
  14                   13

SSx =    120.00
SSy =    110.88
SSxy =  108.50
r =   .94

 

Item 2

What is the correlation between these two variables:

Laughter     Statistics 
    11                 19 
      3                   6 
      5                   6 
    15                 12 
      7                   8 
      6                   7 
      9                 14

SSx =     98.00
SSy =   145.43
SSxy =   85.00
r =   .71

 

Item 3

How much variance is accounted for between these two variables:

Strength        Speed 
    12                 3 
      9                 7 
      6                 9 
      3               11 
      1               15 
      7                 6

SSx =      79.33
SSy =      87.50
SSxy =  – 80.00
r =    – .96
r2 =   .92 or 92% of the mutual variance is accounted for

 

Item 4

What is the correlation between these two variables:

Strength         Peace
    2                     2 
    6                     5 
    7                     8 
  14                   19 
  15                   12 
    9                     8 
    4                     5

SSx =     142.86
SSy =     189.71
SSxy =   147.57
r =   .896
Just for practice here is the r2 =   .80 or 80% of the mutual variance

 

 

 

NOW YOU CHOOSE:
   
Day 5: Correlation
    Bit More About Correlation
    Even More About Correlation
    Calculate Correlation
    Practice Problems
    More Practice Problems
    Word Problems
       
Sim1            Sim2             Sim3
        Sim4            Sim5             Sim6
        Sim7            Sim8             Sim9
    Basic Facts About Correlation
    Vocabulary
    Formulas
    Quiz 5
    Summary

 

Practice Problem Answers: z-scores

October 22, 2008 by  
Filed under Calc Solutions

Item 1

Calculate the z-score, assuming:

X = 10
mean = 50
stdev = 10  

X – mean = – 40 
z score = – 4.0

 

Item 2

Calculate the z-score, assuming:

X = 80
mean = 50
stdev = 15  

X – mean = 30
z score = 2.0

 

Item 3

Calculate the z-score, assuming:

X = 112
mean = 100
stdev = 15  

X – mean = 12
z score = .80

 

Item 4

Calculate the raw score, assuming:

z = 1.5
mean = 115
stdev = 10

z * stdev = 15
X = 130

 

Item 5

Calculate the raw score, assuming:

z = -1.37
mean = 100  

stdev = 20
z * stdev = 27.4
X = 72.6

 

Item 6

Calculate the raw score, assuming:

z =  2.54
mean = 80
stdev = 20  

X = 130.8
2.54*20 = 50.8
50.8 + 80 = 130.8

 

 

 

More Practice Problems ANSWERS: Dispersion

October 22, 2008 by  
Filed under Calc Solutions

Item 6

Calculate the SS of the following scores:

  2
  2
  2
  5
  5
  5
  7

      SS = 24

 

Item 7

Calculate the range and SS of the following scores:

  2
  5
  7
  3
  3
13
19
  4

range = 17
SS = 250

 

Item 8

Calculate the SS and stdev of the following population scores:

11
10
12
  2
  4
  7

SS = 81.33
variance = 13.56

 

Item 9

Calculate the stdev. of the following population:

14
  3
  5
  8
  6
  9

SumX = 45
SS = 73.50
variance = 12.25
stdev. = 3.50

 

Item 10

Calculate the SS of the following sample:

  5
  7
  7
  6
  3
  2

SS = 22.00

 

NOW YOU CHOOSE:
   
Day 3: Dispersion
   
A Bit More About Dispersion
    Even More About Dispersion
       
Range
       
MAD
        
Sum of Squares
       
Variance
        
Standard Deviation
    How To Calculate
       
Range
       
MAD
       
Sum of Squares
       
Variance
       
Standard Deviation
   
Formulas For Dispersion
   
Practice Problems
   
More Practice Problems
   
Basic Facts About Dispersion
   
Vocabulary
    Quiz 3
   
Summary

 

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